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I installed DOS 6.22 on my machine and then installed Win 3.11. My problem is that when I start my computer up, I am in DOS, I have to change to the windows directory, then type win to launch windows 3.1. What do I have to place in my autoexec.bat to launch windows from start up? Thanks for your help.
First, make sure that the windows directory is in your PATH statement.(Example: Path=C:\;C:\DOS;C:\MOUSE;C:\WINDOWS)
Then at the end of the autoexec.bat file put Win or if you want it in enhanced mode put Win/3
(Keep in mind that I'm no expert, so you better make a backup copy of autoexec.bat before you change anything)
Ik, thanks.....worked great....I tried placing the win at the end of my autoexec.bat before...but I wrote win.exe, it did not launch...took the extension off...all worked fine....thanks again
win launched win.com
win.exe does not exist