Right. Where to start??
Came off the A+ course, and now I want to claify this, but I know that even beofre I post this, it isnt going to make sense.
Ok.
Was informed that basically, if you had a 64 bit bus width (as on Pentiums?) you needed to put 64 bit's worth of memory in the banks, otherwise it would not work.
I.E 64bit bus would need 2 x 72 pin SIMMS (apparently 32bit each?) otherwise it wouldnt work...
IS that right??
If so, then what happens if you added 4 SIMMS, 72pin each? that would total 128 bits. Apparently this extra would be ignored, but does that not mean that the RAM on the sticks would also be ignored??
The tutor said we may of been getting confused with memory address and something else, alas she never bothered to explain it.
Someone I spoke to came up with a theory, that RAM operates on a stack system basis. So if we use the above example, the system would use the amount of RAM that the system recognised in the range of bits is needed (in this case the first 2 SIMMS) and then use the other 2 as 'storage', simply passing up the data into the first 2 sticks as the space on them free up...
True/False?
And here's the other bit. If Pentiums already run at 64 bit bus width, what is so special about these new AMD64's?
Also, how are the amount of pins relational to how many bits a SIMM or DIMM is?
Thanks to those who read this, if it dont make sense please let me know!!
Now my head is going to explode.
Hong
