Project : Dual boot two win9x os's

Hi guys i have a working batch file to get this working.

it goes something like this

Batch : (called Change)

attrib -h -r -s c:\msdos.sys

rename c:\msdos.sys wait
rename c:\mike msdos.sys
rename c:\wait mike.

_________________________________
Msdos.sys :

[Paths]
WinDir=C:\WINDOWS
WinBootDir=C:\WINDOWS
HostWinBootDrv=C

[Options]
BootMulti=1
BootGUI=1
DoubleBuffer=1
AutoScan=1
WinVer=4.10.2222
;
;The following lines are required for compatibility with other programs.
;Do not remove them (MSDOS.SYS needs to be >1024 bytes).

_________________________________

Mike :

[Paths]
WinDir=C:\WINDOWS2
WinBootDir=C:\WINDOWS2
HostWinBootDrv=C

[Options]
BootMulti=1
BootGUI=1
DoubleBuffer=1
AutoScan=1
WinVer=4.10.2222
;
;The following lines are required for compatibility with other programs.
;Do not remove them (MSDOS.SYS needs to be >1024 bytes).
__________________________________________

Now with it like this i can run 2 win98se systems on the same hard disk just goto the command prompt type change and reboot (not win as the msdos file has already been loaded and will start the older version of windows).

I know somebody is going to come in and say "yeah but what about your config.sys and autoexec.bat files etc..."

This is what i want include in this batch file.

also can earlier versions of windows (95,98fe) run on say windows 98se dos(command.com)

I had to make a batch like this at work today as i had to make a fresh install of windows but keep his existing installation incase he wants to retrieve something from his old installation.

But im just curious now and want to make the ultimate batch file complete with a little menu system.

Does anybody know the win switch for reboot and not shutdown i.e win /z = power off?


Thanx hope i havent :confused: confused anyone mike :)